W5 APP

Please see attachments for prior assignment

Assignment Instructions

# This is the flower box and it should at the beginning of each assignment# You must add comments to your code # Program name   : Wk5_firstname_lastname.py # Student Name   : Ymmas Azaba # Course              : ENTD220 # Instructor         : My instructor # Date                 : Any Day# Description            : This code shall ….# Copy Wrong      : This is my workYou are going to enhance the prior assignment by doing the following 1) Move all the functions into  Mylib.py2) Use import to include Mylib into the code3) Test the code and make sure that the prior code is still working4) Add the following function into  Mylib    scalc(p1)    p1 will be a string like this “N1, N2, operator”    examples    scalc(“20,30,*”)    the result will be 600     scalc(“50,20,+”)    the result will be 70   scalc(“50,20,-“)    the result will be 30     scalc(“60,20,/”)    the result will be 30 use string functions to parse the first number, the second number, and the operator from the input string.use the prior functions (add, subtract, divide and multiply ) to do the calculations. Submission Instructions:Make sure that you save your code in a text file in this format;W5_firstname_lastname.py 

# Program name :
# Student Name :
# Course : ENTD220
# Instructor :
# Date : 01/24/2020
# Description : Simple Arithmetic
# Copy Wrong : This is my work
#add 2 numbers
def plus(n1,n2):
return n1 + n2
#subtract 2 numbers
def subtract(n1, n2):
return n1 – n2
#multiply 2 numbers
def multiply(n1, n2):
return n1 * n2
#division, n2 should not be zero
def divide(n1, n2):
try:
div = n1/(n2 + 0.0)
print(“The result of %d/%d=%f” % (n1, n2, div))
except ZeroDivisionError as e:
print(“The result of %s/%s = %s” % (n1, n2,”You cannot divide by Zero”))
except Exception :
print(“Invalid input”)
#test the divide function
def test_divide():
print(“————Tests——————“)
divide(5, 0) #catch division by zero
divide(“4”, “2”) #catch invalid number exception
print(“———————————–“)
def IsInRange(lr, hr, n):
return lr < n and n < hr def main(): low = int(input("Enter Lower range:")) high = int(input("Enter Higher range:")) n1 = int(input(“Enter first number:”))
n2 = int(input(“Enter second number:”))
#n1 and n2 must be in range
if IsInRange(low , high, n1) and IsInRange(low , high, n2):
add = plus(n1 , n2)
sub = subtract(n1 , n2)
mul = multiply(n1 , n2)
#use print formating, %d = double, %f = float, %s = string
print(“The result of %d+%d=%d” % (n1, n2, add))
print(“The result of %d-%d=%d” % (n1, n2, sub))
print(“The result of %d*%d=%d” % (n1, n2, mul))
divide(n1, n2)
else:
print(“Errors: input out of range”)

while True:
main()
yn = str(input(“Continue Looping Y/N:”))
if yn == “N”:
break
test_divide()
print(“Thanks for using our calculator!”)

I implemented the exception in divide function, its purpose is to
trap divide by zero exceptions and other exceptions such as TypeError.