Grade 12 electromagnetism written question
Total 3 question
Don't use plagiarized sources. Get Your Custom Essay on
High school Grade 12 physics question
Just from $13/Page
Need to be print off and hand writing then scan it back as pdf file
Formula sheet provided as the file datasheet
Question file called U4 written
1
Physics 30 Unit
4
Electromagnetism Exam Part B
Name: __________________ Date: ________________
Written Response #1
Use the following information to answer the next question.
• Describe two experiments or observations which show EMR behaving like a
wave. Explain how the observed behaviors are ‘wave-like’. (2 marks)
• Describe two experiments or observations which show EMR behaving like a
particle. Explain how the observed behaviors are ‘particle-like’. (2 marks)
Electromagnetic radiation (EMR) has been modeled by physicists as a wave and as
a photon which has both wave and particle characteristics.
2
Written Response #2 Name: ______________
Zoe conducted an experiment to determine the focal length of a convex lens. She used
an optics bench to illuminate an object and project a real image of it onto a screen and
recorded the data in the chart below:
Object
Distance
(cm)
Inverse of distance
to object
(cm-1)
Image Distance
(cm)
Inverse of distance
to image
(cm-1)
25.0
100.0
27.0
77.1
31.0
56.4
35.0
46.7
42.0
38.2
• Complete the above chart (2 marks)
Optics Bench
Illuminated
Object
Convex Lens Screen
3
• Graph the data to produce a straight line. Be sure to include: (3 marks)
o Labels for the x and y axes, including correct units , and
o a title
• Use the graph to determine the focal length of the convex lens.
(2 marks)
4
Written Response #3 Name: ______________
Use the following information to answer the next question
You must completely analyze the data and identify the metal. In your response,
• Identify the region of the electromagnetic spectrum to which the incident
frequency radiation belongs. (1 mark)
• Provide a graph of the results on the next page. (3 marks)
• Determine the value, with units, of the slope. Identify the significance of the
slope. (2 marks)
Name: ______________
A student performed a photoelectric effect experiment in which he exposed an
unidentified metal to various frequencies of incident electromagnetic radiation and
measure the stopping voltage of the emitted photoelectrons.
He calculated the maximum kinetic energy of the emitted photoelectrons.
His results are given in the table below.
Frequency of incident electromagnetic
Radiation (1015 Hz)
1.3 1.4 1.5 1.6 1.7 1.8
Maximum kinetic energy of emitted
Photoelectrons (10-19 J)
1.0 1.8 2.4 3.1 3.8 4.4
The teacher provided the student with the following table of work functions for
selected metals.
Metal Work Function
(eV)
Na 2.28
Co 3.90
Pb 4.14
Ag 4.73
Pt 6.35
5
• Determine the values, with units, of the x-intercept and the y-intercept.
Identify the significance of each of the intercepts. Use your results to identify
the metal. Justify your answer. (3 marks)
(Title)
(y
–
a
xi
s)
(x – axis)
P
H
Y
S
IC
S
D
A
T
A
S
H
E
E
T
C
on
st
an
t
s
A
cc
el
e
r
at
io
n
D
ue
t
o
G
r
a
v
it
y
N
ea
r
E
ar
th
.
.
…
…
…
…
…
…
…
..
| _ › a g
| =
9
.8
1
m
/s
2
G
ra
v
it
at
io
na
l
C
on
st
an
t .
…
..
G
=
6
.6
7
×
1
0
–1
1
N
. m
2
/k
g2
R
ad
iu
s
of
E
ar
th
..
…
…
…
…
…
r e
=
6
.3
7
×
1
0
6
m
M
as
s
of
E
ar
th
..
…
…
…
…
…
…
M
e
=
5
.9
7
×
1
0
2
4
kg
E
le
m
en
ta
r
y
C
ha
rg
e
…
…
…
..
e
=
1
.6
0
×
1
0
–1
9
C
C
ou
lo
m
b’
s
L
aw
C
on
st
an
t .
.
k
=
8
.9
9
×
1
0
9
N
. m
2
/C
2
E
le
ct
ro
n
V
ol
t .
…
…
…
…
…
…
..
1
eV
=
1
.6
0
×
1
0
–1
9
J
In
de
x
of
R
ef
ra
ct
io
n
of
A
ir
.
n
=
1
.0
0
S
p
ee
d
of
L
ig
ht
i
n
V
ac
uu
m
.
c
=
3
.0
0
×
1
0
8
m
/s
P
la
nc
k’
s
C
on
st
an
t .
…
…
…
…
.
h
=
6
.6
3
×
1
0
–3
4
J.
s
h
=
4
.1
4
×
1
0
–1
5
eV
. s
A
to
m
ic
M
as
s
U
n
it
..
…
…
…
..
u
=
1
.6
6
×
1
0
–2
7
kg
P
h
ys
ic
s
P
ri
n
ci
p
le
s
U
n
if
or
m
m
ot
io
n
(b
al
an
ce
d
fo
rc
es
)
U
n
if
or
m
ly
a
cc
el
er
at
ed
m
ot
io
n
(u
nb
al
an
ce
d
fo
rc
es
)
C
ir
cu
la
r
m
ot
io
n
(u
nb
al
a
n
ce
d
fo
rc
es
)
W
or
k-
en
er
g
y
th
eo
re
m
C
on
se
rv
at
io
n
of
m
om
en
tu
m
C
on
se
rv
at
io
n
of
e
ne
rg
y
C
on
se
rv
at
io
n
of
m
as
s-
en
er
g
y
C
on
se
rv
at
io
n
of
c
ha
rg
e
C
on
se
rv
at
io
n
of
n
uc
le
on
s
W
av
e-
pa
rt
ic
le
d
u
al
it
y
P
ar
ti
cl
es
C
h
ar
ge
M
as
s
A
lp
ha
P
ar
ti
cl
e .
…
…
…
…
…
…
…
.
+
2
e
6.
65
×
1
0
–2
7
kg
E
le
ct
ro
n
…
…
…
…
…
…
…
…
…
…
..
–
1e
9.
11
×
1
0
–3
1
kg
P
ro
to
n
…
…
…
…
…
…
…
…
…
…
…
..
+
1e
1.
67
×
1
0
–2
7
kg
N
eu
tr
on
…
…
…
…
…
…
…
…
…
…
…
0
1.
67
×
1
0
–2
7
kg
F
ir
st
-G
e
n
er
at
io
n
F
er
m
io
n
s
C
h
ar
ge
M
as
s
E
le
ct
ro
n
…
…
…
…
…
…
…
…
…
…
..
–
1e
0.
51
1
M
eV
/c
2
P
os
it
ro
n
…
…
…
…
…
…
…
…
…
…
..
+
1e
0.
51
1
M
eV
/c
2
E
le
ct
ro
n
ne
ut
ri
no
, ν
..
…
…
…
…
0
<
5
0
eV
/c
2
E
le
ct
ro
n
an
ti
ne
ut
ri
no
, _
_ ν
…
…
.
0
<
5
0
eV
/c
2
U
p
q
u
ar
k
, u
..
…
…
…
…
…
…
…
…
.
+
2
__
3
e
~5
M
eV
/c
2 *
A
nt
i-
up
a
nt
iq
u
ar
k
, _
_ u
…
…
…
…
.
–
2
__
3
e
~5
M
eV
/c
2 *
D
ow
n
qu
ar
k
, d
..
…
…
…
…
…
…
..
–
1
__
3
e
~1
0
M
eV
/c
2 *
A
nt
i-
do
w
n
an
ti
qu
ar
k
, _
_ d
…
…
..
+
1
__
3
e
~1
0
M
eV
/c
2 *
* C
u
rr
en
t
m
o
de
ls
s
ee
m
t
o
su
gg
es
t
a
si
g
n
ifi
ca
nt
ly
l
ow
er
m
as
s
of
t
he
se
q
u
ar
k
s
th
an
t
ho
se
i
n
th
is
t
ab
le
.
P
re
fi
xe
s
U
se
d
w
it
h
S
I
U
n
it
s
E
xp
on
en
ti
al
P
re
fi
x
S
ym
b
ol
V
al
u
e
at
to
..
…
…
…
…
a
…
…
…
…
..
10
–1
8
fe
m
to
..
…
…
…
f
…
…
…
…
..
10
–1
5
pi
co
..
…
…
…
…
p
…
…
…
…
..
10
–1
2
na
no
..
…
…
…
..
n
…
…
…
…
..
10
–
9
m
ic
ro
..
…
…
…
µ
..
…
…
…
..
10
–
6
m
il
li
..
…
…
…
..
m
..
…
…
…
..
10
–3
ce
nt
i .
…
…
…
…
c
…
…
…
…
..
10
–2
de
ci
..
…
…
…
…
d
…
…
…
…
..
10
–1
de
k
a
..
…
…
…
.d
a
…
…
…
…
10
1
he
ct
o
..
…
…
…
h
…
…
…
…
..
10
2
k
il
o
…
…
…
…
..
k
…
…
…
…
..
10
3
m
eg
a
..
…
…
…
M
..
…
…
…
.1
0
6
g
ig
a .
…
…
…
…
.G
..
…
…
…
..
10
9
te
ra
…
…
…
…
…
T
..
…
…
…
..
10
12
E
Q
U
A
T
IO
N
S
K
in
e
m
at
ic
s
_ › v a
ve
=
∆
_
› d
__
_
∆
t
_ › d
=
_ › v f
t
–
1
__
2
_ ›
a
t2
_ › a
av
e
=
∆
_ › v
__
_
∆
t
_ › d
=
( _
› v f
+
_
› v i
__
__
__
2
) t
_ › d
=
_
› v i
t
+
1
__
2
_ ›
a
t2
v f
2
=
v
i2
+
2
a
d
| _ › v c
| =
2π
r
__
__
T
| _ › a c
| =
v2
__
r
=
4π
2
r
__
__
_
T
2
D
yn
am
ic
s
_ › a
=
_
_ › F
ne
t
__
__
m
| __ › F g
| =
G
m
1m
2
__
__
__
_
r2
| __ › F f
| =
µ
| __ › F N
|
| _ › g |
=
G
m
__
__
r2
_ ›
F
s
=
–
k_
›
x
_ › g
=
__
›
F
g
__
_
m
M
om
en
tu
m
a
n
d
E
n
er
gy
_ › p
=
m
_ › v
E
k
=
1
__
2
m
v2
_ ›
F
∆
t
=
m
∆
_ › v
E
p
=
m
gh
W
=
| _
›
F
|
| _ › d|
c
os
θ
E
p
=
1 __
2
k
x2
W
=
∆
E
P
=
W
__
t
W
av
es
T
=
2
π √
__
m
__
k
m
=
h
i
__
_
h
o
=
–
d
i
__
__
d
o
T
=
2
π
√ __
_
l __
g
1
__
f
=
1 __
_
d
o
+
1 __
_
d
i
T
=
1 __
f
si
nθ
1
__
__
_
si
nθ
2
=
n
2
__
_
n 1
=
v 1
__
v 2
=
λ
1
__
_
λ 2
v
=
f
λ
λ
=
d
s
in
θ
__
__
__
n
f
=
(
v
__
__
__
v
±
v s
) f s
λ
=
xd
__
_
n
l
E
le
ct
ri
ci
ty
a
n
d
M
ag
n
et
is
m
|_ ›
F
e |
=
kq
1q
2
__
__
__
r2
∆V
=
∆
E
__
_ q
| _
›
E
|
=
kq
__
_
r2
I
=
q
__
t
_ ›
E
=
__
›
F
e
__
_ q
| __ › F m
| =
I
l ⊥
| __ › B |
| _
›
E
|
=
∆V
__
_
∆
d
| __ › F m
| =
q
v ⊥
| __ › B |
A
to
m
ic
P
h
ys
ic
s
W
=
h
f 0
E
=
h
f
=
h
c
__
_
λ
E
k
m
ax
=
q
eV
st
o
p
N
=
N
0 ( 1
__
2
) n
Q
u
an
tu
m
M
ec
h
an
ic
s
an
d
N
u
cl
ea
r
P
h
ys
ic
s
∆
E
=
∆
m
c2
E
=
p
c
p
=
h
__
λ
∆
λ
=
h
__
_
m
c(
1
–
co
sθ
)
T
ri
go
n
o
m
et
ry
a
n
d
G
eo
m
et
ry
si
nθ
=
op
p
os
it
e
__
__
__
__
__
hy
p
ot
en
us
e
co
sθ
=
ad
ja
ce
nt
__
__
__
__
__
hy
p
ot
en
us
e
ta
nθ
=
op
p
os
it
e
__
__
__
_
ad
ja
ce
nt
c2
=
a
2
+
b
2
a
__
__
_
si
n
A
=
b
__
__
_
si
n
B
=
c
__
__
_
si
n
C
c2
=
a
2
+
b
2
–
2
a
b
c
os
C
S
lo
p
e
m
=
∆y
__
_
∆
x
A
re
a
R
ec
ta
ng
le
=
l
w
T
ri
an
gl
e
=
1 __
2
a
b
C
ir
cl
e
=
π
r2
C
ir
cu
m
fe
re
n
ce
C
ir
cl
e
=
2
π
r
G
ra
p
h
in
g
C
al
cu
la
to
r
W
in
d
ow
F
or
m
at
x:
[
x m
in
, x
m
ax
, x
sc
l]
y:
[
y m
in
, y
m
ax
, y
sc
l]
