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2/8/2020 Module 4 – CH 4 HW – PHYS 102 January 2020 Online, section Wicker (0005), Spring 2020 | WebAssign
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PHYS 102 January 2020 Online, section Wicker (0005), Spring 2020
Module 4 – CH 4 HW (Homework)
INSTRUCTOR
Katharine Wicker
Embry Riddle Aeronautical University, FL
Current Score
QUESTION
POINTS
TOTAL SCORE
54.28/100 54.3%
SUN, FEB 9, 2020
6:59 PM HST
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When answering the homework problems be careful to represent the
units properly and place a space between the numeric value and the unit
(for example 5.0 m/s, not 5.0m/s). Your response will be marked wrong if
you enter the wrong units in your answer. You may enter numeric values
as all numbers or in scienti�c notation. For example if your answer is
36,000,000 you may enter all the numbers or to enter the answer in
scienti�c notation, you would convert 36,000,000 to 3.6×107 and enter
3.6e7 (NOTE the lower case e). Likewise, a numeric value of 0.00000037
would be 3 7e 7
Assignment Submission & Scoring
Assignment Submission
For this assignment, you submit answers by
question parts. The number of submissions
remaining for each question part only changes
if you submit or change the answer.
Assignment Scoring
Your last submission is used for your score.
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2/8/2020 Module 4 – CH 4 HW – PHYS 102 January 2020 Online, section Wicker (0005), Spring 2020 | WebAssign
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The water in the plumbing in a house is at a gauge pressure of 380,000 Pa. What force does this cause on the top of the tank
inside a water heater if the area of the top is 0.9 m2? (Ignore atmospheric pressure.)
342,000 N
Show My Work (Optional)
A viewing window on the side of a large tank at a public aquarium measures 41 in. by 46 in. The average gauge pressure from
the water is 6 psi. What is the total outward force on the window?
11,316 lbs
Show My Work (Optional)
would be 3.7e-7
Acceptable units are:
Those listed in previous chapter homework
Force F = N or lb (if dealing with pressure in psi)
Weight density = lb/ft^3
Weight = lb
Pressure = psi or Pa in the MKS units
NOTES:
1. When you enter your answer for an essay question, you will receive
10% of the points possible for the question to let you know you entered
an answer. Your instructor will review your answer and adjust the points
depending on the quality and completeness of your answers.
2. If you need help for other questions, use the Read It link that will take
you to the portion of the text dealing with the question.
3. When entering answers with a value less that 1.0, enter the numeric
value accurate to four decimal places (three signi�cant �gures).
Description
2/8/2020 Module 4 – CH 4 HW – PHYS 102 January 2020 Online, section Wicker (0005), Spring 2020 | WebAssign
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A small statue is recovered in an archaeological dig. Its weight is measured to be 59.0 lb and its volume 0.09 ft3.
(a) What is the statue’s weight density?
(b) What substance is it, most likely?
diamond
silver
juniper wood
iron
lead
Show My Work (Optional)
A certain part of an aircraft engine has a volume of 1.2 ft3.
(a) Find the weight of the piece when it is made of lead.
(b) If the same piece is made of aluminum, what is its weight?
201.6 lb
Determine how much weight is saved by using aluminum instead of lead.
Show My Work (Optional)
The depth of the Pacific Ocean in the Mariana Trench is 36,198 ft. What is the gauge pressure at this depth?
Show My Work (Optional)
A storage tank 29 m high is filled with gasoline. (Assume the tank is open and exposed to the atmosphere at the top.)
(a) Find the gauge pressure at the bottom of the tank.
(b) Calculate the magnitude of the force produced by the fluid that acts on a square access hatch at the bottom of the
tank that measures 0.6 m by 0.6 m.
Show My Work (Optional)
655.56 lb/ft
16,180.51 p
4. –/7.14 points My Notes Ask Your Teacher
2/8/2020 Module 4 – CH 4 HW – PHYS 102 January 2020 Online, section Wicker (0005), Spring 2020 | WebAssign
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A modern-day zeppelin holds 9,070 m3 of helium. Compute its maximum payload at sea level. (Assume the helium and air to be
at 0°C and 1 atm.)
Problem Statement: A modern-day zeppelin holds 7,800 m3 of helium. Compute its maximum payload at sea level. (Assume the
helium and air to be at 0°C and 1 atm.)
Step 1: Write down what you know in symbolic form:
For this problem we are given the volume in cubic meters, therefore we will use the fact that the weight density of a substance
can be represented as the mass density of the substance times the acceleration due to gravity: Dw = Dg (see page 146 in the
text).
Volume: V = 7800 m3
Mass Density of air: D(air) = 1.29 kg/m3
Mass Density of helium: D(helium) = 0.18 kg/m3
Step 2: Write down what you don’t know in symbolic form:
Weight of helium: W = ?
Buoyant force: Fb = ?
Maximum payload or Net Force: Fnet = ?
Step 3: Find an equation that contains what you know and what you don’t know:
Weight of helium: W = D(helium) x g x V(of helium)
Buoyant force: Fb = D(air) x g x V(air)
In this case V(of helium) = V(air) = V
Net Force: Fnet = Fb – W
Step 4: Solve the equation for what you don’t know:
Net Force: Fnet = Fb – W = D(air) x g x V – D(helium) x g x V = [D(air) – D(helium)] x g xV
Step 5: Plug in (substitute) what you know and you will find out what you don’t know:
Net Force: Fnet = Fb – W = [D(air) – D(helium)] x g x V = [1.29 kg/m3 – 0.18 kg/m3 ] x 9.8 m/s2 x 7,800 m3 = 1.11 kg/m3 x
9.8 m/s2 x 7,800 m3 = 84,848. 4 kg m/s2 (m3/m3) = 84,848.4 N
Show My Work (Optional)
A juniper-wood plank measuring 0.36 ft by 1 ft by 17 ft is totally submerged in water.
(a) What is its weight?
(b) What is the buoyant force acting on it?
(c) What is the size and the direction of the net force on it?
size
direction —Select—
Show My Work (Optional)
10080.398
2/8/2020 Module 4 – CH 4 HW – PHYS 102 January 2020 Online, section Wicker (0005), Spring 2020 | WebAssign
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A rectangular block of ice with dimensions 2 m by 2 m by 0.2 m floats on water. A person weighing 980 N wants to stand on the
ice. Would the ice sink below the surface of the water?
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The wing of an airplane has an average cross-sectional area of 13 m2 and experiences a lift force of 63,000 N. What is the
average difference in the air pressure (in N/m^2)between the top and bottom of the wing?
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Yes
No
2/8/2020 Module 4 – CH 4 HW – PHYS 102 January 2020 Online, section Wicker (0005), Spring 2020 | WebAssign
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Describe the four phases of matter. Compare their external, observable properties.
Solids: (Select all that apply.)
Liquids: (Select all that apply.)
Gases: (Select all that apply.)
Plasmas: (Select all that apply.)
Compare the nature of the forces between atoms or molecules (or both) in the solid, liquid, and gas phases.
Solids:
are generally good conductors of electricity and interact strongly with magnetic fields
can be compressed or squeezed into a smaller volume readily
flow readily, conforming to the shape of their container
have a well-defined boundary or surface
are rigid, and generally retain their shape unless distorted by a force
are generally good conductors of electricity and interact strongly with magnetic fields
can be compressed or squeezed into a smaller volume readily
flow readily, conforming to the shape of their container
have a well-defined boundary or surface
are rigid, and generally retain their shape unless distorted by a force
are generally good conductors of electricity and interact strongly with magnetic fields
can be compressed or squeezed into a smaller volume readily
flow readily, conforming to the shape of their container
have a well-defined boundary or surface
are rigid, and generally retain their shape unless distorted by a force
are generally good conductors of electricity and interact strongly with magnetic fields
can be compressed or squeezed into a smaller volume readily
flow readily, conforming to the shape of their container
have a well-defined boundary or surface
are rigid, and generally retain their shape unless distorted by a force
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Liquids:
Gases:
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The attractive forces bind particles together, but not rigidly so; each atom or molecule can move about relative
to the others but is always in contact with other atoms or molecules.
The attractive forces between particles are too weak to bind them together; atoms or molecules move about
freely with high speed and are widely separated, only coming into contact when they collide.
The attractive forces are so strong that the atoms or molecules are rigidly bound to their neighbors and can
only vibrate.
The attractive forces bind particles together, but not rigidly so; each atom or molecule can move about relative
to the others but is always in contact with other atoms or molecules.
The attractive forces between particles are too weak to bind them together; atoms or molecules move about
freely with high speed and are widely separated, only coming into contact when they collide.
The attractive forces are so strong that the atoms or molecules are rigidly bound to their neighbors and can
only vibrate.
The attractive forces bind particles together, but not rigidly so; each atom or molecule can move about relative
to the others but is always in contact with other atoms or molecules.
The attractive forces between particles are too weak to bind them together; atoms or molecules move about
freely with high speed and are widely separated, only coming into contact when they collide.
The attractive forces are so strong that the atoms or molecules are rigidly bound to their neighbors and can
only vibrate.
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Why is it that a person can lay still on a “bed” of nails (see the figure below) without suffering any serious injuries but would
incur severe puncture wounds to his feet if he tried to stand barefoot on the same “bed”?
Show My Work (Optional)
A person lying still on a “bed” of nails has his weight distributed over a much larger area than if he were standing, and
so the force (pressure ✕ unit area) on the person’s skin is much greater when lying down. Because the upward force is
much greater when lying down, the net force (weight − force from nails) is closer to zero, and the nails do not
puncture the skin.
A person lying still on a “bed” of nails takes up far more volume than a standing person, and so the buoyant force
exerted by the air is much greater on a lying person than a standing person. Because the net force (weight − buoyant
force) is much less, the pressure (force/unit area) is much less for a lying person, and the nails do not puncture the
skin.
The weight of a person lying still on a “bed” of nails is much less than the weight of a standing person, and so the
pressure (force/unit area) on the person’s skin is much less when lying down. Because the pressure is much less when
lying down, the nails do not puncture the skin.
A person lying still on a “bed” of nails has his weight distributed over a much larger area than if he were standing, and
so the pressure (force/unit area) on the person’s skin is much less when lying down. Because the pressure is much less
when lying down, the nails do not puncture the skin.
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Would the weight density of water be different on the Moon than it is on Earth?
What about the mass density?
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The pressure in the air along the upper surface of an aircraft’s wing (in flight) is lower than the pressure along the lower surface.
Compare the speed of the air flowing over the wing to that of the air flowing under the wing.
Score: 0.718 out of 7.18
Comment:
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The air flowing over the wing travels at a higher speed which creates
a lower pressure on top of the wing than underneath. This effect
creates the lift required to elevate an aircraft off the ground and
continue the flight. The wind below the wing is moving faster
creating a higher pressure also.
Yes
No
The mass density would stay the same.
The mass density would not stay the same.
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